Mathematical Immaturity

2.8 Exercises

In each of Exercises 13 through 20, a function $T: V_3 \rightarrow V_3$ is defined by the formula given for $T(x, y, z),$ where $(x, y, z)$ is an arbitrary point in $V_3.$ In each case, determine whether $T$ is one-to-one on $V_3.$ If it is, describe its range $T(V_3);$ for each point $(u, v, w)$ in $T(V_3),$ let $(x, y, z) = T^{-1}(u, v, w)$ and give formulas for determining $x,$ $y,$ and $z$ in terms of $u,$ $v,$ and $w.$

19.$\quad$ $T(x, y, z) = (x, x + y, x + y + z).$

Solution. $\quad$ Let $A = (x, y, z)$ and $B = (p, q, r)$ be two points in $V_3.$ Then \begin{align*} T(A) &= (x, x + y, x + y + z) \\ T(B) &= (p, p + q, p + q + r) \end{align*} If $T(A) = T(B)$ then we have $x = p,$ $x + y = p + q = x + q,$ making $y = q,$ and by extension, $x + y + z = x + y + r,$ making $z = r.$ As such, $T(A) = T(B),$ implies $A = B,$ which means $T$ one-to-one on $V_3.$ The range of $T$ is $V_3,$ and for each point $(u, v, w)$ in $T(V_3),$ if we let $(x, y, z) = T^{-1}(u, v, w),$ we have the formulas \begin{align*} x &= u, \quad y = v - u,\quad z = w - v. \quad \blacksquare \end{align*}